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← JEE Main 2022 · 26 Jun · Shift 2
PhysicsInteger+4 / -1Question 56 of 90

JEE Main 2022 · 26 Jun · Shift 2, Physics question 56

A set of 20 tuning forks is arranged in a series of increasing frequencies. If each fork gives 4 beats with respect to the preceding fork and the frequency of the last fork is twice the frequency of the first, then the frequency of last fork is ______ Hz.

Answer and worked solution

Official answer: 152

Arithmetic sequence. f20=f1+19×4=2f1f_{20}=f_1+19\times4=2f_1, so f1=76f_1=76 Hz and f20=152f_{20}=152 Hz.

Answer: 152

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