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← JEE Main 2022 · 26 Jun · Shift 2
PhysicsInteger+4 / -1Question 51 of 90

JEE Main 2022 · 26 Jun · Shift 2, Physics question 51

A ball is projected vertically upward with an initial velocity of 50 ms−1^{-1} at t=0t=0 s. At t=2t=2 s, another ball is projected vertically upward with same velocity. At t=t= ______ s, second ball will meet the first ball (g=10g=10 ms−2^{-2}).

Answer and worked solution

Official answer: 6

Positions. y1=50t−5t2y_1=50t-5t^2 and y2=50(t−2)−5(t−2)2y_2=50(t-2)-5(t-2)^2.

Equal. 0=−100+20t−200=-100+20t-20, so t=6t=6 s.

Answer: 6