JEE Main 2022 · 26 Jun · Shift 2 · Physics Q50

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A sinusoidal wave $y(t)=40\sin\left(10\times10^6\pi t\right)$ is amplitude modulated by another sinusoidal wave $x(t)=20\sin(1000\pi t)$ . The amplitude of minimum frequency component of modulated signal is :

0.5

0.25

Answer and worked solution

Official answer: D

AM spectrum. Carrier amplitude 40 and modulation index $\mu=\frac{20}{40}=\frac12$ ; each sideband has amplitude $\frac{\mu A_c}2=10$ .

Lowest frequency is the lower sideband: amplitude 10.

(D)

Topics:Modulation

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JEE Main 2022 · 26 Jun · Shift 2, Physics question 50