JEE Main 2022 · 26 Jun · Shift 2 · Physics Q40

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PhysicsSingle correct+4 / -1Question 40 of 90

Sixty four conducting drops each of radius 0.02 m and each carrying a charge of $5\ \mu$ C are combined to form a bigger drop. The ratio of surface density of bigger drop to the smaller drop will be :

1:4

4:1

1:8

8:1

Answer and worked solution

Official answer: B

Big drop. 64 drops make radius $4r$ and charge $64q$ .

Surface density $\sigma\propto\dfrac Q{R^2}$ : $\dfrac{64}{16}=4$ , so $4:1$ .

(B)

Topics:Conductors and charge distribution

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JEE Main 2022 · 26 Jun · Shift 2, Physics question 40