JEE Main 2022 · 26 Jun · Shift 2 · Physics Q39

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PhysicsSingle correct+4 / -1Question 39 of 90

A parallel plate capacitor with plate area A and plate separation d = 2 m has a capacitance of $4\ \mu$ F. The new capacitance of the system if half of the space between them is filled with a dielectric material of dielectric constant K = 3 (as shown in figure) will be :

Two parallel plates a distance d apart; a dielectric slab (K = 3) of thickness d/2 and the full plate area fills the half of the gap next to the right plate.

2\ \mu

32\ \mu

6\ \mu

8\ \mu

Answer and worked solution

Official answer: C

Slab of thickness $\frac d2$ across the full area acts as two capacitors in series: $C'=\dfrac{\varepsilon_0A}{\frac d2+\frac d{2K}}=\dfrac{2K}{K+1}C$ .

Value. $\dfrac64\times4=6\ \mu$ F.

(C)

Topics:Dielectrics

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JEE Main 2022 · 26 Jun · Shift 2, Physics question 39