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← JEE Main 2022 · 26 Jun · Shift 2
PhysicsSingle correct+4 / -1Question 31 of 90

JEE Main 2022 · 26 Jun · Shift 2, Physics question 31

The dimension of mutual inductance is :

Choose one option
Answer and worked solution

Official answer: C

Mutual inductance M=ΦIM=\dfrac\Phi I: ML2T−2A−1A=[ML2T−2A−2]\dfrac{ML^2T^{-2}A^{-1}}{A}=[ML^2T^{-2}A^{-2}].

(C)