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← JEE Main 2022 · 26 Jun · Shift 2
MathematicsInteger+4 / -1Question 22 of 90

JEE Main 2022 · 26 Jun · Shift 2, Mathematics question 22

Let pp and qq be two real numbers such that p+q=3p+q=3 and p4+q4=369p^4+q^4=369. Then (1p+1q)−2\left(\dfrac1p+\dfrac1q\right)^{-2} is equal to ______.

Answer and worked solution

Official answer: 4

Let s=pqs=pq. p4+q4=(9−2s)2−2s2=81−36s+2s2=369p^4+q^4=(9-2s)^2-2s^2=81-36s+2s^2=369, so s2−18s−144=0s^2-18s-144=0: s=24s=24 or −6-6.

Real roots need 9−4s≥09-4s\ge0, so s=−6s=-6.

Value. (p+qpq)−2=(s3)2=4\left(\dfrac{p+q}{pq}\right)^{-2}=\left(\dfrac s3\right)^2=4.

Answer: 4