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← JEE Main 2022 · 26 Jun · Shift 1
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JEE Main 2022 · 26 Jun · Shift 1, Physics question 55

A 10 Ω10\ \Omega, 20 mH coil carrying constant current is connected to a battery of 20 V through a switch. Now after switch is opened current becomes zero in 100 μ\mus. The average e.m.f. induced in the coil is ______ V.

Answer and worked solution

Official answer: 400

Current. I=2010=2I=\dfrac{20}{10}=2 A.

Average emf. LΔIΔt=0.02×210−4=400L\dfrac{\Delta I}{\Delta t}=0.02\times\dfrac2{10^{-4}}=400 V.

Answer: 400