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JEE Main 2022 · 26 Jun · Shift 1, Physics question 54

The elongation of a wire on the surface of the earth is 10−410^{-4} m. The same wire of same dimensions is elongated by 6×10−56\times10^{-5} m on another planet. The acceleration due to gravity on the planet will be ______ ms−2^{-2}. (Take acceleration due to gravity on the surface of earth = 10 ms−2^{-2})

Answer and worked solution

Official answer: 6

Same wire and mass. Elongation ∝\propto load ∝g\propto g: g′=10×6×10−510−4=6g'=10\times\dfrac{6\times10^{-5}}{10^{-4}}=6 m s−2^{-2}.

Answer: 6

Topics:Hooke's law and elastic moduliVariation of g
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