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JEE Main 2022 · 26 Jun · Shift 1, Physics question 43

An aluminium wire is stretched to make its length, 0.4% larger. The percentage change in resistance is :

Choose one option
Answer and worked solution

Official answer: C

Constant volume. R=ρL2V∝L2R=\rho\dfrac{L^2}{V}\propto L^2, so ΔRR=2ΔLL=0.8%\dfrac{\Delta R}R=2\dfrac{\Delta L}L=0.8\%.

(C)

Topics:Ohm's law and resistivity
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