JEE Main 2022 · 26 Jun · Shift 1 · Physics Q42

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PhysicsSingle correct+4 / -1Question 42 of 90

The magnetic flux through a coil perpendicular to its plane is varying according to the relation $\phi=\left(5t^3+4t^2+2t-5\right)$ Weber. If the resistance of the coil is 5 ohm, then the induced current through the coil at t = 2 s will be,

15.6 A

16.6 A

17.6 A

18.6 A

Answer and worked solution

Official answer: A

emf. $\varepsilon=\dfrac{d\phi}{dt}=15t^2+8t+2=78$ V at $t=2$ s.

Current. $\dfrac{78}5=15.6$ A.

(A)

Topics:Faraday's and Lenz's laws

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JEE Main 2022 · 26 Jun · Shift 1, Physics question 42