JEE Main 2022 · 26 Jun · Shift 1 · Physics Q36

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PhysicsSingle correct+4 / -1Question 36 of 90

The variation of acceleration due to gravity (g) with distance (r) from the center of the earth is correctly represented by :

(Given R = radius of earth)

g rises linearly from 0 to a peak at r = R, then falls as a curve beyond R

g against r: linear rise from the origin to a peak at R, then a decreasing curve.

g constant up to r = R, then falls as a curve beyond R

g against r: constant up to R, then a decreasing curve.

g decreasing as a curve for all r from 0

g against r: a decreasing curve from near r = 0.

g rises as an upward-curving arc to a sharp peak at r = R, then falls

g against r: concave-up rise to a cusp at R, then a decreasing curve.

Answer and worked solution

Official answer: A

Inside (uniform earth): $g=\dfrac{GMr}{R^3}\propto r$ , a straight line from the origin. Outside: $g\propto\dfrac1{r^2}$ , falling. The peak is at $r=R$ .

(A)

Topics:Variation of g

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JEE Main 2022 · 26 Jun · Shift 1, Physics question 36