JEE Main 2022 · 26 Jun · Shift 1 · Physics Q35

← JEE Main 2022 · 26 Jun · Shift 1

PhysicsSingle correct+4 / -1Question 35 of 90

A thin circular ring of mass M and radius R is rotating with a constant angular velocity 2 rad s $^{-1}$ in a horizontal plane about an axis vertical to its plane and passing through the center of the ring. If two objects each of mass m be attached gently to the opposite ends of a diameter of ring, the ring will then rotate with an angular velocity (in rad s $^{-1}$ ).

\dfrac M{(M+m)}

\dfrac{(M+2m)}{2M}

\dfrac{2M}{(M+2m)}

\dfrac{2(M+2m)}M

Answer and worked solution

Official answer: C

Angular momentum is conserved. $MR^2(2)=(M+2m)R^2\omega$ , so $\omega=\dfrac{2M}{M+2m}$ .

(C)

Topics:Angular momentum and its conservation Moment of inertia

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JEE Main 2022 · 26 Jun · Shift 1, Physics question 35