JEE Main 2022 · 25 Jun · Shift 2 · Physics Q42

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PhysicsSingle correct+4 / -1Question 42 of 90

A sinusoidal voltage $V(t)=210\sin3000t$ volt is applied to a series LCR circuit in which $L=10$ mH, $C=25\ \mu$ F and $R=100\ \Omega$ . The phase difference ( $\Phi$ ) between the applied voltage and resultant current will be :

\tan^{-1}(0.17)

\tan^{-1}(9.46)

\tan^{-1}(0.30)

\tan^{-1}(13.33)

Answer and worked solution

Official answer: A

Reactances. $X_L=3000\times0.01=30\ \Omega$ ; $X_C=\dfrac1{3000\times25\times10^{-6}}\approx13.33\ \Omega$ .

Phase. $\tan\Phi=\dfrac{X_L-X_C}R=\dfrac{16.67}{100}\approx0.17$ .

(A)

Topics:LCR circuits and resonance Reactance and impedance

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JEE Main 2022 · 25 Jun · Shift 2, Physics question 42