JEE Main 2022 · 25 Jun · Shift 2 · Physics Q39

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PhysicsSingle correct+4 / -1Question 39 of 90

Two cells of same emf but different internal resistances $r_1$ and $r_2$ are connected in series with a resistance $R$ . The value of resistance $R$ , for which the potential difference across second cell is zero, is :

r_2-r_1

r_1-r_2

r_1

r_2

Answer and worked solution

Official answer: A

Current. $I=\dfrac{2E}{R+r_1+r_2}$ .

Second cell's terminal voltage zero: $E=Ir_2$ , so $R+r_1+r_2=2r_2$ , i.e. $R=r_2-r_1$ .

(A)

Topics:EMF and internal resistance

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JEE Main 2022 · 25 Jun · Shift 2, Physics question 39