JEE Main 2022 · 25 Jun · Shift 2 · Physics Q38

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PhysicsSingle correct+4 / -1Question 38 of 90

Two metallic plates form a parallel plate capacitor. The distance between the plates is ' $d$ '. A metal sheet of thickness $\dfrac d2$ and of area equal to area of each plate is introduced between the plates. What will be the ratio of the new capacitance to the original capacitance of the capacitor?

2:1

1:2

1:4

4:1

Answer and worked solution

Official answer: A

Metal sheet reduces the effective gap to $d-\frac d2=\frac d2$ , so $C'=\dfrac{\varepsilon_0A}{d/2}=2C$ : ratio $2:1$ .

(A)

Topics:Dielectrics Capacitors and capacitance

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JEE Main 2022 · 25 Jun · Shift 2, Physics question 38