JEE Main 2022 · 25 Jun · Shift 2 · Chemistry Q71

← JEE Main 2022 · 25 Jun · Shift 2

ChemistrySingle correct+4 / -1Question 71 of 90

The metal ion (in gaseous state) with lowest spin-only magnetic moment value is

\mathrm{V^{2+}}

\mathrm{Ni^{2+}}

\mathrm{Cr^{2+}}

\mathrm{Fe^{2+}}

Answer and worked solution

Official answer: B

Unpaired electrons (free ions): $\mathrm{V^{2+}}$ $d^3$ (3), $\mathrm{Ni^{2+}}$ $d^8$ (2), $\mathrm{Cr^{2+}}$ $d^4$ (4), $\mathrm{Fe^{2+}}$ $d^6$ (4). Fewest in $\mathrm{Ni^{2+}}$ , $\mu=\sqrt8\approx2.83$ BM.

(B)

Topics:Transition element properties Electronic configuration

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JEE Main 2022 · 25 Jun · Shift 2, Chemistry question 71