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← JEE Main 2022 · 25 Jun · Shift 2
ChemistrySingle correct+4 / -1Question 70 of 90

JEE Main 2022 · 25 Jun · Shift 2, Chemistry question 70

The number of bridged oxygen atoms present in compound B formed from the following reactions is
Pb(NO3)2→673 KA+PbO+O2\mathrm{Pb(NO_3)_2\xrightarrow{673\ K}A+PbO+O_2}
A→DimeriseB\mathrm{A\xrightarrow{Dimerise}B}

Choose one option
Answer and worked solution

Official answer: A

A. 2Pb(NO3)2→673 K4NO2+2PbO+O2\mathrm{2Pb(NO_3)_2\xrightarrow{673\ K}4NO_2+2PbO+O_2}, so A is NO2\mathrm{NO_2}.

B. It dimerises to N2O4\mathrm{N_2O_4}, O2N-NO2\mathrm{O_2N\text{-}NO_2}, joined by an N-N bond: no bridging oxygen.

(A)

Topics:Group 15