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← JEE Main 2022 · 25 Jun · Shift 1
PhysicsInteger+4 / -1Question 58 of 90

JEE Main 2022 · 25 Jun · Shift 1, Physics question 58

The total current supplied to the circuit as shown in figure by the 5 V battery is ______ A.

A circular loop of wire with a 5 V cell on its left arc and a 5 Ω resistor on its right arc. Inside, a star of three resistors meets at a centre node: 5 Ω and 5 Ω to two points on the upper arc (joined to each other by plain wire) and 2.5 Ω to the bottom of the loop.
Answer and worked solution

Official answer: 2

Nodes. The two upper ends of the star are joined by the wire arc, forming one node P; the battery and the right-hand 5 Ω run between P and the bottom node Q.

Star branch. The two 5 Ω in parallel (2.5 Ω) in series with 2.5 Ω: 5 Ω from P to Q.

Total. 5∥5=2.5 Ω5\parallel5=2.5\ \Omega, so I=52.5=2I=\dfrac5{2.5}=2 A.

Answer: 2