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← JEE Main 2022 · 25 Jun · Shift 1
PhysicsInteger+4 / -1Question 57 of 90

JEE Main 2022 · 25 Jun · Shift 1, Physics question 57

A resistor develops 300 J of thermal energy in 15 s, when a current of 2 A is passed through it. If the current increases to 3 A, the energy developed in 10 s is ______ J.

Answer and worked solution

Official answer: 450

Resistance. 300=22R(15)300=2^2R(15) gives R=5 ΩR=5\ \Omega.

New energy. 32×5×10=4503^2\times5\times10=450 J.

Answer: 450