JEE Main 2022 · 25 Jun · Shift 1 · Physics Q37

← JEE Main 2022 · 25 Jun · Shift 1

PhysicsSingle correct+4 / -1Question 37 of 90

The relation between root mean square speed ( $v_{\rm rms}$ ) and most probable speed ( $v_p$ ) for the molar mass M of oxygen gas molecule at the temperature of 300 K will be :

v_{\rm rms}=\sqrt{\dfrac23}\,v_p

v_{\rm rms}=\sqrt{\dfrac32}\,v_p

v_{\rm rms}=v_p

v_{\rm rms}=\sqrt{\dfrac13}\,v_p

Answer and worked solution

Official answer: B

Speeds. $v_{\rm rms}=\sqrt{\dfrac{3RT}M}$ and $v_p=\sqrt{\dfrac{2RT}M}$ , so $v_{\rm rms}=\sqrt{\dfrac32}\,v_p$ .

(B)

Topics:Molecular speeds

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JEE Main 2022 · 25 Jun · Shift 1, Physics question 37