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← JEE Main 2022 · 24 Jun · Shift 2
PhysicsInteger+4 / -1Question 58 of 90

JEE Main 2022 · 24 Jun · Shift 2, Physics question 58

A circular coil of 1000 turns each with area 1 m21\ \mathrm m^2 is rotated about its vertical diameter at the rate of one revolution per second in a uniform horizontal magnetic field of 0.07 T. The maximum voltage generation will be ______ V.

Answer and worked solution

Official answer: 440

Peak emf. ε0=NBAω=1000×0.07×1×2π≈439.8\varepsilon_0=NBA\omega=1000\times0.07\times1\times2\pi\approx439.8 V.

Nearest integer 440.

Answer: 440