JEE Main 2022 · 24 Jun · Shift 1 · Physics Q36

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PhysicsSingle correct+4 / -1Question 36 of 90

A block of mass 10 kg starts sliding on a surface with an initial velocity of $9.8\ \mathrm{ms^{-1}}$ . The coefficient of friction between the surface and block is 0.5. The distance covered by the block before coming to rest is :

[use $g=9.8\ \mathrm{ms^{-2}}$ ]

4.9 m

9.8 m

12.5 m

19.6 m

Answer and worked solution

Official answer: B

Deceleration. $a=\mu g=0.5\times9.8=4.9$ m s $^{-2}$ .

Distance. $s=\dfrac{v^2}{2a}=\dfrac{9.8^2}{2\times4.9}=9.8$ m.

(B)

Topics:Friction Motion in a straight line

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JEE Main 2022 · 24 Jun · Shift 1, Physics question 36