JEE Main 2022 · 24 Jun · Shift 1 · Chemistry Q63 · Dronacharya Exams

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ChemistryList match+4 / -1Question 63 of 90

Match List - I with List - II :

Choose the most appropriate answer from the options given below :

List - I

A
$\mathrm{[PtCl_4]^{2-}}$
B
$\mathrm{BrF_5}$
C
$\mathrm{PCl_5}$
D
$\mathrm{[Co(NH_3)_6]^{3+}}$

List - II

I
$sp^3d$
II
$d^2sp^3$
III
$dsp^2$
IV
$sp^3d^2$

A

(A)-(II), (B)-(IV), (C)-(I), (D)-(III)

B

(A)-(III), (B)-(IV), (C)-(I), (D)-(II)

C

(A)-(III), (B)-(I), (C)-(IV), (D)-(II)

D

(A)-(II), (B)-(I), (C)-(IV), (D)-(III)

Answer and worked solution

Official answer: B

Hybridisation.

$\mathrm{[PtCl_4]^{2-}}$ : square planar Pt(II), $dsp^2$ (III).
$\mathrm{BrF_5}$ : 5 bond pairs and 1 lone pair, $sp^3d^2$ (IV).
$\mathrm{PCl_5}$ : trigonal bipyramidal, $sp^3d$ (I).
$\mathrm{[Co(NH_3)_6]^{3+}}$ : low-spin $d^6$ inner-orbital octahedral, $d^2sp^3$ (II).

(B)

Topics:Hybridisation Valence bond theory

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