Skip to content
dronacharya.ai
← JEE Main 2022 · 24 Jun · Shift 1
ChemistrySingle correct+4 / -1Question 62 of 90

JEE Main 2022 · 24 Jun · Shift 1, Chemistry question 62

Consider the following pairs of electrons

(A) (a) n=3, l=1, ml=1, ms=+12n=3,\ l=1,\ m_l=1,\ m_s=+\frac12

(b) n=3, l=2, ml=1, ms=+12n=3,\ l=2,\ m_l=1,\ m_s=+\frac12

(B) (a) n=3, l=2, ml=−2, ms=−12n=3,\ l=2,\ m_l=-2,\ m_s=-\frac12

(b) n=3, l=2, ml=−1, ms=−12n=3,\ l=2,\ m_l=-1,\ m_s=-\frac12

(C) (a) n=4, l=2, ml=2, ms=+12n=4,\ l=2,\ m_l=2,\ m_s=+\frac12

(b) n=3, l=2, ml=2, ms=+12n=3,\ l=2,\ m_l=2,\ m_s=+\frac12

The pairs of electrons present in degenerate orbitals is/are :

Choose one option
Answer and worked solution

Official answer: B

Degenerate orbitals have the same nn and ll (in a free atom).

  • (A): l=1l=1 and l=2l=2, different subshells.
  • (B): both n=3n=3, l=2l=2: two 3d orbitals, degenerate.
  • (C): n=4n=4 and n=3n=3, different shells.

Only (B).

(B)

Topics:Quantum numbers
← Previous questionNext question →