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← JEE Main 2021 · 24 Feb · Shift 1
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JEE Main 2021 · 24 Feb · Shift 1, Physics question 21

The coefficient of static friction between a wooden block of mass 0.5 kg and a vertical rough wall is 0.2. The magnitude of horizontal force that should be applied on the block to keep it adhere to the wall will be _______ N. [g = 10 m s−2^{-2}]

Answer and worked solution

Official answer: 25

Friction balances weight. μF=mg\mu F=mg: F=50.2=25F=\frac{5}{0.2}=25 N.

Answer: 25

Topics:Friction