JEE Main 2021 · 24 Feb · Shift 1 · Physics Q20

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PhysicsSingle correct+4 / -1Question 20 of 90

In a Young's double slit experiment, the width of the one of the slit is three times the other slit. The amplitude of the light coming from a slit is proportional to the slit-width. Find the ratio of the maximum to the minimum intensity in the interference pattern.

4 : 1

2 : 1

1 : 4

3 : 1

Answer and worked solution

Official answer: A

Amplitudes 3 : 1, so $\dfrac{I_{max}}{I_{min}}=\left(\dfrac{3+1}{3-1}\right)^2=4$ .

(A)

Topics:Interference and Young's double slit

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JEE Main 2021 · 24 Feb · Shift 1, Physics question 20