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← JEE Main 2021 · 24 Feb · Shift 1
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JEE Main 2021 · 24 Feb · Shift 1, Mathematics question 83

Let P=[3−1−220α3−50]P=\begin{bmatrix}3&-1&-2\\2&0&\alpha\\3&-5&0\end{bmatrix}, where α ∈ ℝ. Suppose Q = [qij_{ij}] is a matrix satisfying PQ = kI3_3 for some non-zero k ∈ ℝ. If q23=−k8q_{23}=-\dfrac k8 and ∣Q∣=k22|Q|=\dfrac{k^2}2, then α2^2 + k2^2 is equal to _______.

Answer and worked solution

Official answer: 17

Q = kP⁻¹. Then ∣Q∣=k3∣P∣=k22|Q|=\frac{k^3}{|P|}=\frac{k^2}2 gives ∣P∣=2k|P|=2k, and ∣P∣=12α+20|P|=12\alpha+20.

Entry. q23=k∣P∣C32=−(3α+4)2=−k8q_{23}=\frac{k}{|P|}C_{32}=\frac{-(3\alpha+4)}2=-\frac k8, so k=4(3α+4)k=4(3\alpha+4). With k=6α+10k=6\alpha+10: α=−1\alpha=-1, k=4k=4.

Answer: 17