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JEE Main 2017 · 9 Apr · Shift 1, Physics question 2

A car is standing 200 m behind a bus, which is also at rest. The two start moving at the same instant but with different forward accelerations. The bus has acceleration 2 m/s2^2 and the car has acceleration 4 m/s2^2. The car will catch up with the bus after a time of :

Choose one option
Answer and worked solution

Official answer: C

Relative to the bus, the car starts 200 m behind with acceleration 2 m/s²: 12⋅2⋅t2=200\frac12\cdot2\cdot t^2=200, so t=200=102t=\sqrt{200}=10\sqrt2 s.

Topics:Relative velocityMotion in a straight line
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