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JEE Main 2017 · 9 Apr · Shift 1, Physics question 1

A physical quantity P is described by the relation
P=a1/2b2c3d−4P=a^{1/2}b^2c^3d^{-4}
If the relative errors in the measurement of a, b, c and d respectively, are 2%, 1%, 3% and 5%, then the relative error in P will be :

Choose one option
Answer and worked solution

Official answer: C

ΔPP=12(2%)+2(1%)+3(3%)+4(5%)=1+2+9+20=32%.\frac{\Delta P}P=\frac12(2\%)+2(1\%)+3(3\%)+4(5\%)=1+2+9+20=32\%.

Topics:Errors in measurement
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