JEE Main 2017 · 9 Apr · Shift 1 · Chemistry Q38

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ChemistrySingle correct+4 / -1Question 38 of 90

Adsorption of a gas on a surface follows Freundlich adsorption isotherm. Plot of $\log\dfrac xm$ versus log p gives a straight line with slope equal to 0.5, then :

( $\dfrac xm$ is the mass of the gas adsorbed per gram of adsorbent)

Adsorption is independent of pressure.

Adsorption is proportional to the pressure.

Adsorption is proportional to the square root of pressure.

Adsorption is proportional to the square of pressure.

Answer and worked solution

Official answer: C

$\log\frac xm=\log k+\frac1n\log p$ with slope $\frac1n=0.5$ , so $\frac xm=kp^{1/2}$ : proportional to the square root of pressure.

Topics:Adsorption

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JEE Main 2017 · 9 Apr · Shift 1, Chemistry question 38