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← JEE Main 2017 · 8 Apr · Shift 1
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JEE Main 2017 · 8 Apr · Shift 1, Physics question 27

The V-I characteristic of a diode is shown in the figure. The ratio of forward to reverse bias resistance is :

Diode I-V curve: in forward bias the current is 10 mA at 0.7 V, 15 mA at about 0.75 V and 20 mA at 0.8 V (the voltage labels are printed as .7 and .8); in reverse bias the current is −1 μA at −10 V.
Choose one option
Answer and worked solution

Official answer: B

Forward bias (from the linear part of the graph): Rf=0.8−0.7(20−10)×10−3=10 ΩR_f=\dfrac{0.8-0.7}{(20-10)\times10^{-3}}=10\ \Omega. Reverse bias: Rr=1010−6=107 ΩR_r=\dfrac{10}{10^{-6}}=10^7\ \Omega.
RfRr=10−6.\frac{R_f}{R_r}=10^{-6}.