JEE Main 2017 · 8 Apr · Shift 1 · Physics Q26

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PhysicsSingle correct+4 / -1Question 26 of 90

Two deuterons undergo nuclear fusion to form a Helium nucleus. Energy released in this process is : (given binding energy per nucleon for deuteron = 1.1 MeV and for helium = 7.0 MeV)

30.2 MeV

32.4 MeV

23.6 MeV

25.8 MeV

Answer and worked solution

Official answer: C

$E=4\times7.0-2\times(2\times1.1)=28-4.4=23.6$ MeV.

Topics:Mass defect and binding energy Nuclear fission and fusion

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JEE Main 2017 · 8 Apr · Shift 1, Physics question 26