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← JEE Main 2017 · 8 Apr · Shift 1
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JEE Main 2017 · 8 Apr · Shift 1, Physics question 8

In an experiment a sphere of aluminium of mass 0.20 kg is heated upto 150°C. Immediately, it is put into water of volume 150 cc at 27°C kept in a calorimeter of water equivalent to 0.025 kg. Final temperature of the system is 40°C. The specific heat of aluminium is :

(take 4.2 Joule = 1 calorie)

Choose one option
Answer and worked solution

Official answer: D

Heat gained by the water and calorimeter: (0.150+0.025)×4200×13=9555(0.150+0.025)\times4200\times13=9555 J. Heat lost by the aluminium: 0.20×c×110=22c0.20\times c\times110=22c. So c=434c=434 J/kg-°C.