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← JEE Main 2017 · 8 Apr · Shift 1
MathematicsSingle correct+4 / -1Question 63 of 90

JEE Main 2017 · 8 Apr · Shift 1, Mathematics question 63

Let z∈Cz\in\mathbb C, the set of complex numbers. Then the equation, 2∣z+3i∣−∣z−i∣=02|z+3i|-|z-i|=0 represents :

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Answer and worked solution

Official answer: A

With z=x+iyz=x+iy, 4(x2+(y+3)2)=x2+(y−1)24\left(x^2+(y+3)^2\right)=x^2+(y-1)^2, i.e.
x2+y2+263y+353=0.x^2+y^2+\frac{26}3y+\frac{35}3=0.
The centre is (0,−133)\left(0,-\frac{13}3\right) and r2=1699−1059=649r^2=\frac{169}9-\frac{105}9=\frac{64}9: a circle of radius 83\frac83.