JEE Main 2017 · 8 Apr · Shift 1 · Mathematics Q62

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MathematicsSingle correct+4 / -1Question 62 of 90

Let p(x) be a quadratic polynomial such that p(0) = 1. If p(x) leaves remainder 4 when divided by $x-1$ and it leaves remainder 6 when divided by $x+1$ ; then :

p(2) = 11

p(2) = 19

p(−2) = 19

p(−2) = 11

Answer and worked solution

Official answer: C

$p(x)=ax^2+bx+1$ with $a+b+1=4$ and $a-b+1=6$ , so $a=4$ , $b=-1$ . Then $p(-2)=16+2+1=19$ .

Topics:Theory of equations (higher degree)

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JEE Main 2017 · 8 Apr · Shift 1, Mathematics question 62