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← JEE Main 2017 · 8 Apr · Shift 1
ChemistrySingle correct+4 / -1Question 38 of 90

JEE Main 2017 · 8 Apr · Shift 1, Chemistry question 38

Addition of sodium hydroxide solution to a weak acid (HA) results in a buffer of pH 6. If ionisation constant of HA is 10−510^{-5}, the ratio of salt to acid concentration in the buffer solution will be :

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Answer and worked solution

Official answer: C

pH=pKa+log⁡[salt][acid]\text{pH}=pK_a+\log\dfrac{[\text{salt}]}{[\text{acid}]}: 6=5+log⁡[salt][acid]6=5+\log\dfrac{[\text{salt}]}{[\text{acid}]}, so the ratio is 10 : 1.