JEE Main 2017 · 2 Apr · Shift 1 · Physics Q20

← JEE Main 2017 · 2 Apr · Shift 1

PhysicsSingle correct+4 / -1Question 20 of 90

In a coil of resistance 100 Ω, a current is induced by changing the magnetic flux through it as shown in the figure. The magnitude of change in flux through the coil is :

Induced current (amp) against time: a straight line falling from 10 A at t = 0 to zero at 0.5 s.

200 Wb

225 Wb

250 Wb

275 Wb

Answer and worked solution

Official answer: C

The charge through the coil is the area under the I-t graph, $q=\frac12\times10\times0.5=2.5$ C. Since $q=\dfrac{\Delta\Phi}R$ :
$\Delta\Phi=qR=2.5\times100=250\text{ Wb}.$

Topics:Faraday's and Lenz's laws

← Previous question Next question →

JEE Main 2017 · 2 Apr · Shift 1, Physics question 20