JEE Main 2017 · 2 Apr · Shift 1 · Physics Q19

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PhysicsSingle correct+4 / -1Question 19 of 90

When a current of 5 mA is passed through a galvanometer having a coil of resistance 15 Ω, it shows full scale deflection. The value of the resistance to be put in series with the galvanometer to convert it into a voltmeter of range 0 − 10 V is :

1.985\times10^3

2.045\times10^3

2.535\times10^3

4.005\times10^3

Answer and worked solution

Official answer: A

$R=\dfrac V{I_g}-G=\dfrac{10}{5\times10^{-3}}-15=1985\ \Omega$ .

Topics:Moving coil galvanometer Ammeters and voltmeters

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JEE Main 2017 · 2 Apr · Shift 1, Physics question 19