JEE Main 2017 · 2 Apr · Shift 1 · Physics Q8

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A copper ball of mass 100 gm is at a temperature T. It is dropped in a copper calorimeter of mass 100 gm, filled with 170 gm of water at room temperature. Subsequently, the temperature of the system is found to be 75°C. T is given by :

(Given : room temperature = 30°C, specific heat of copper = 0.1 cal/gm°C)

800°C

885°C

1250°C

825°C

Answer and worked solution

Official answer: B

Heat gained by the calorimeter and water: $(100\times0.1+170\times1)(75-30)=8100$ cal. Heat lost by the ball: $100\times0.1\times(T-75)=10(T-75)$ .

So $T-75=810$ and $T=885^\circ$ C.

Topics:Calorimetry and specific heat

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JEE Main 2017 · 2 Apr · Shift 1, Physics question 8