JEE Main 2017 · 2 Apr · Shift 1 · Physics Q7

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PhysicsSingle correct+4 / -1Question 7 of 90

The variation of acceleration due to gravity g with distance d from centre of the earth is best represented by (R = Earth's radius) :

g rising, concave up, without limit

Graph of g against d, with R marked: a concave-up curve rising from O.

g rising as a concave-up curve to R, then falling

Graph of g against d, with R marked: a concave-up rise to a peak at R, then a decreasing curve.

g rising as a concave-up curve to R, then falling linearly

Graph of g against d, with R marked: a concave-up rise to a peak at R, then a straight fall.

g rising linearly to R, then falling as a curve

Graph of g against d, with R marked: a straight rise from O to a peak at R, then a decreasing curve.

Answer and worked solution

Official answer: D

Inside a uniform earth $g=\dfrac{GM}{R^3}d$ , linear in $d$ . Outside, $g=\dfrac{GM}{d^2}$ . So a straight rise to a peak at R, then a $\frac1{d^2}$ fall: graph (4).

Topics:Variation of g

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JEE Main 2017 · 2 Apr · Shift 1, Physics question 7