JEE Main 2016 · 10 Apr · Shift 1 · Mathematics Q80

← JEE Main 2016 · 10 Apr · Shift 1

MathematicsSingle correct+4 / -1Question 80 of 90

Equation of the tangent to the circle, at the point (1, −1), whose centre is the point of intersection of the straight lines x − y = 1 and 2x + y = 3 is :

4x + y − 3 = 0

x + 4y + 3 = 0

3x − y − 4 = 0

x − 3y − 4 = 0

Answer and worked solution

Official answer: B

The centre is $\left(\frac43,\frac13\right)$ . The radius to (1, −1) has direction (1, 4), so the tangent is $x+4y=c$ ; through (1, −1), $x+4y+3=0$ .

Topics:Tangents and normals

← Previous question Next question →

JEE Main 2016 · 10 Apr · Shift 1, Mathematics question 80