JEE Main 2016 · 10 Apr · Shift 1 · Mathematics Q79

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MathematicsSingle correct+4 / -1Question 79 of 90

A straight line through origin O meets the lines 3y = 10 − 4x and 8x + 6y + 5 = 0 at points A and B respectively. Then O divides the segment AB in the ratio :

2 : 3

1 : 2

4 : 1

3 : 4

Answer and worked solution

Official answer: C

On $y=mx$ : $x_A=\frac{10}{3m+4}$ and $x_B=-\frac5{2(3m+4)}$ . So $OA:OB=10:\frac52=4:1$ (O lies between A and B).

Topics:Distance and section formulae

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JEE Main 2016 · 10 Apr · Shift 1, Mathematics question 79