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← JEE Main 2016 · 10 Apr · Shift 1
MathematicsSingle correct+4 / -1Question 64 of 90

JEE Main 2016 · 10 Apr · Shift 1, Mathematics question 64

Let A be a 3 × 3 matrix such that A2−5A+7I=OA^2-5A+7I=O.

Statement - I : A−1=17(5I−A)A^{-1}=\dfrac17(5I-A).

Statement - II : The polynomial A3−2A2−3A+IA^3-2A^2-3A+I can be reduced to 5(A − 4I).

Then :

Choose one option
Answer and worked solution

Official answer: C

A(5I−A)=7IA(5I-A)=7I, so I is true. With A2=5A−7IA^2=5A-7I, A3=18A−35IA^3=18A-35I and
A3−2A2−3A+I=18A−35I−10A+14I−3A+I=5A−20I=5(A−4I).A^3-2A^2-3A+I=18A-35I-10A+14I-3A+I=5A-20I=5(A-4I).
So II is true too.