JEE Main 2016 · 10 Apr · Shift 1 · Chemistry Q36

← JEE Main 2016 · 10 Apr · Shift 1

ChemistrySingle correct+4 / -1Question 36 of 90

An aqueous solution of a salt $\ce{MX2}$ at certain temperature has a van't Hoff factor of 2. The degree of dissociation for this solution of the salt is :

0.33

0.50

0.67

0.80

Answer and worked solution

Official answer: B

$\ce{MX2 -> M^2+ + 2X-}$ gives $i=1+2\alpha=2$ , so $\alpha=0.5$ .

Topics:van't Hoff factor

← Previous question Next question →

JEE Main 2016 · 10 Apr · Shift 1, Chemistry question 36