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← JEE Main 2016 · 10 Apr · Shift 1
ChemistrySingle correct+4 / -1Question 35 of 90

JEE Main 2016 · 10 Apr · Shift 1, Chemistry question 35

If 100 mole of HX2OX2\ce{H2O2} decompose at 1 bar and 300 K, the work done (kJ) by one mole of OX2(g)\ce{O2(g)} as it expands against 1 bar pressure is :
2 HX2OX2(l)⇌2 HX2O(l)+OX2(g)\ce{2H2O2(l) <=> 2H2O(l) + O2(g)}
(R = 8.3 J K−1^{-1} mol−1^{-1})

Choose one option
Answer and worked solution

Official answer: B

100 mol of HX2OX2\ce{H2O2} gives 50 mol of OX2\ce{O2}, which does W=nRT=50×8.3×300=124.5W=nRT=50\times8.3\times300=124.5 kJ against 1 bar.

The question says "by one mole of OX2\ce{O2}", which would be 2.49 kJ (not an option); the derived key takes the intended quantity to be the work done by all the oxygen formed.