JEE Main 2016 · 9 Apr · Shift 1 · Physics Q9

PhysicsSingle correct+4 / -1Question 9 of 90

The ratio of work done by an ideal monoatomic gas to the heat supplied to it in an isobaric process is :

\dfrac35

\dfrac23

\dfrac32

\dfrac25

Answer and worked solution

Official answer: D

At constant pressure $W=nR\Delta T$ and $Q=nC_p\Delta T=\frac52nR\Delta T$ , so $\frac WQ=\frac25$ .

JEE Main 2016 · 9 Apr · Shift 1, Physics question 9