JEE Main 2016 · 3 Apr · Shift 1 · Chemistry Q37

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ChemistrySingle correct+4 / -1Question 37 of 90

The equilibrium constant at 298 K for a reaction $\ce{A + B <=> C + D}$ is 100. If the initial concentration of all the four species were 1 M each, then equilibrium concentration of D (in mol L $^{-1}$ ) will be :

0.182

0.818

1.818

1.182

Answer and worked solution

Official answer: C

Q = 1 < K, so the reaction goes forward by x: $\dfrac{(1+x)^2}{(1-x)^2}=100$ gives $\dfrac{1+x}{1-x}=10$ and $x=\frac9{11}=0.818$ . So [D] = 1.818 M.

Topics:Law of mass action and Kc, Kp

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JEE Main 2016 · 3 Apr · Shift 1, Chemistry question 37