JEE Main 2016 · 3 Apr · Shift 1 · Chemistry Q36

ChemistrySingle correct+4 / -1Question 36 of 90

18 g glucose ( $\ce{C6H12O6}$ ) is added to 178.2 g water. The vapor pressure of water (in torr) for this aqueous solution is :

7.6

76.0

752.4

759.0

Answer and worked solution

Official answer: C

0.1 mol glucose in 9.9 mol water gives a water mole fraction of 0.99, so $p=0.99\times760=752.4$ torr.

JEE Main 2016 · 3 Apr · Shift 1, Chemistry question 36