JEE Main 2015 · 11 Apr · Shift 1 · Mathematics Q84

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MathematicsSingle correct+4 / -1Question 84 of 90

A plane containing the point (3, 2, 0) and the line $\dfrac{x-1}1=\dfrac{y-2}5=\dfrac{z-3}4$ also contains the point :

(0, −3, 1)

(0, 7, 10)

(0, 7, −10)

(0, 3, 1)

Answer and worked solution

Official answer: B

The plane contains $(3,2,0)$ , $(1,2,3)$ and the direction $(1,5,4)$ . Its normal is $(1,5,4)\times(-2,0,3)=(15,-11,10)$ , so the plane is $15x-11y+10z=23$ . The point $(0,7,10)$ : $-77+100=23$ ✓.

Topics:Equation of a plane

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JEE Main 2015 · 11 Apr · Shift 1, Mathematics question 84